posted May 11, 2005 02:36 AM         

SOULMATES….
A SEAL, AT LAST, SET.
A MATE, SOUL OASES MET.
AS SALT TO SEA,
AS SEA TO SALT;
AS MUSE TO TALE,
AS TALE TO MUSE;
SO ALSO TO US,
AS META-SOULS, SALUTE.

SOULMATES #2

LET US ASSUME MUTE ELMS, AS STELA,
TO USE AS SLATES, AS TOMES TO SET TALES
TO AMUSE A MUSE.

(Stela=an inscribed slab used as a monument)

ANAGRAMS OF SOULMATES

META SOULS
ASSUME LOT,
SAME LOTUS
A MUSES LOT.

USE ALMOST,
A MUST LOSE,
ALMOST USE

O’ SAME LUST
MET A SOULS…
A MUTE LOSS.

©2005, Intrinsic Development.

posted May 21, 2005 09:37 AM         

since u said there aint many people who are interested in lexigrams so just 2 make u happy i wrote a computer program that can generate for you anagrams .. and (hopefully .. since they far far far out number the anagrams ..)lexigrams..

but with that you will have to give me a LOT OF HELP!
look, i do not have a computer at home.. i rote the program on paper.. i log on 2 the net thru internet cafes..which do not have C++ loaded on their computers..
so what v r gonna need is :
1.) the C++ programming language (available in the matket)(not C not java not any other but C++..the program can be made on java but since i dont know the language properly so..)
2.) a dictionary loaded on the computer (since yiu will need C++ and the dictionary at the same time it is important that you install atleast 1 of them on ur machine) and also... u need 2 understand that:

let me make it clear thru examples..
if you have the word fayte , then the no. of ways in which you can arrange it is 5! that is 1*2*3*4*5 = 120.. if you have a 6 letter word or phrase (the blank space also included) then the no. of ways are 6! (=720) .. and so on..so now fayte v have here 2 cases :
1.) if the total no. of characters are less than 8 or 8 the program is going to give you all the anagrams .. (you may view 300 at a time or more depending on how much the screen of the C++ language allows)
2.) if you have a word or phrase of more than 8 characters .. then well.. v have no choice but v will have to make use of the dictionary..(because viewing all the anagrams /lexigrams then will be i think.. impossible..)
how to do that since the dictionary is so huge?
look fayte at a time what u du is that u give say 500 (n if u run the program and the output is given within few seconds ..(DU TELL ME HOW MANY!)THEN V CAN INCREASE THE NO. TO 1000 OR EVEN MORE)'probable' words picked up from the dictioonary to the program.. and then the program is going to generate 1 anagram (or lexigram) and then it is going to run thru the words you have input and if there is a match ..it is going to print that word..
look fayte ..the words that you will pick up from the dictionary ..you will obviously select them then copy them and then paste them... the CONDITION IS THAT YOU WILL HAVE TO DU IT IN SUCH A WAY THAT ALL THE WORDS COME UP SEPERATED BY A BLANK SPACE.. YOU GOT THAT??? IE .. YOU ARE NOT ALLOWED TO ENTER THEM IN DIFERENT LINES..

so are u interested? obviously if this works.. it will be flawless.. since the computer is a machine..
so r v a team?

a bull-eagle team?

posted May 21, 2005 10:07 AM         

#include<iostream.h>
#include<conio.h>
#include<stdio.h>
void main ()
{
clrscr;
int i=0,j=0,k=0,l=0;
char an[4];
cout<<"enter a 4 letter word .. if you enter a blankspace then it will also be counted as a letter..ie enter a word or phrase of 4 characters .. the blank space included (and then press enter)(if there is any error and this program does not show an output withinn seconds u press control and break together): ";
cin>>an;
for(l=0;l<4;l++)
for(k=0;k<4;k++)
for(j=0;j<4;j++)
for(i=0;i<4;i++)
{
int x[4],flag=0,pp=0,qq=0;
x[0]=i;
x[1]=j;
x[2]=k;
x[3]=l;
for(pp=0;pp<4;pp++)for(qq=0;qq<4;qq++)if (pp!=qq) if(x[pp]==x[qq])flag=1;
if (flag==0)
{
an[0]=w[i];
an[1]=w[j];
an[2]=w[k];
an[3]=w[l];
cout<<an<<"\n";
}
}
getch();
}

send me the output of the program fayte . n if there is any error then send that.. may be that u wont b able 2 copy n paste . so plz b kind enuf 2 type it.
love
kush